Showing Logout in Header

Corporal Joined: Nov 17, 2004 Posts: 52

I want to place a "logout" button in the header part of the theme I am using. This "logout" will be shown only when user is logged in.
How can I do that?

Thanks

Sergeant Joined: Nov 05, 2004 Posts: 148

This should work. Just put the $login wherever you want it to show on your page. Remember to include the $login variable in the global section of your theme.

Code:

/* User info */
cookiedecode($user);/* Get cookie info */
$ip = $_SERVER["REMOTE_ADDR"];
$uname = $cookie[1];

if (!isset($uname)) {
$uname = "$ip";
$guest = 1;
}
if (is_admin($admin)) {/* Display if administrator */
$login = ""._ADMIN." <a href=\"admin.php?op=logout\"> "._LOGOUT." </a> ";/* Admin:[ Logout ] */
}
if (is_user($user)) {/* Display if registered user */
$login .= "<a href=\"modules.php?name=Your_Account&op=logout\"> "._LOGOUT." </a>";
}
else {/* Display if anonymous user */
$login .= ""._BWEL.";
}

Corporal Joined: Nov 17, 2004 Posts: 52

Thanks for the reply.
I am using the login block that comes with 7.5 but it doesnt have a "logut" option after login. What I want is just to show "logout", not "login" in the header of theme since login will be shown in Login Block.
Can you tell me in which file I should put the code? (header.htm / theme.php)

Sergeant Joined: Nov 05, 2004 Posts: 148

The name ($login) is just a variable that you can place anywhere in your theme files that you would like it to show up on your page. BTW I was just too lazy to change the actual name $login to $logoff. I took it from a more complete code that shows a login field if an anonymous user is detected or a welcome message and logoff link if a registered user is detected.

Corporal Joined: Mar 30, 2005 Posts: 56

So where exactly does this code go